题目内容
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在如下图所示电路中,已知R1=5Ω, R2=2Ω, R3= R4=10Ω,uS1=10V, uS2=4V。用节点电压法求各支路电流()。
A.i1 = (ua - ub)/R1=0.5A i2 = (uc - ub)/R2=-1.5A i3 = ub/R3=0.5A
B.i1 = (ua - ub)/R1=1A i2 = (uc - ub)/R2=-0.5A i3 = ub/R3=0.5A
C.i4 = (ua – uc)/R4=0.6A i5 =i1 + i4=1.6A i6 =i2 - i4= - 1.1A
D.i4 = (ua – uc)/R4=1.6A i5 =i1 + i4=1.2A i6 =i2 - i4= - 1.2A
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